(1/x^5)-(4/x^4)-(12/x^3)=0

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Solution for (1/x^5)-(4/x^4)-(12/x^3)=0 equation: 


D( x )

x^4 = 0

x^3 = 0

x^5 = 0

x^4 = 0

x^4 = 0

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x^3 = 0

x^3 = 0

1*x^3 = 0 // : 1

x^3 = 0

x = 0

x^5 = 0

x^5 = 0

1*x^5 = 0 // : 1

x^5 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/(x^5)-(12/(x^3))-(4/(x^4)) = 0

1/(x^5)-12*x^-3-4*x^-4 = 0

1*x^-5-12*x^-3-4*x^-4 = 0

(1*x^0-12*x^2-4*x^1)/(x^5) = 0 // * x^10

x^5*(1*x^0-12*x^2-4*x^1) = 0

x^5

1-12*x^2-4*x = 0

1-12*x^2-4*x = 0

DELTA = (-4)^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+4)/(-12*2) or x = (4-64^(1/2))/(-12*2)

x = -1/2 or x = 1/6

x in { -1/2, 1/6} 

x in { -1/2, 1/6 }

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